differential of functions (2006-07-01)

I study math.

(ex)' = ex

I differentiated those functions...

y = ex ---> y' = ex
y = sin x ---> y' = cos x
y = cos x ---> y' = -sin x
y = logex ---> y' = 1 / x

Comments

y = tan x ---> y' = 1 / ((cos x) ^ 2)

Posted by NI-Lab. : July 4, 2006 (Tue)

tags: cj1

Posted by NI-Lab. (@nilab)